HackerLand University has the following grading policy:

Every student receives a grade in the inclusive range from 0 to 100.
Any grade less than 40 is a failing grade.
Sam is a professor at the university and likes to round each student’s grade according to these rules:

If the difference between the grade and the next multiple of 5 is less than 3, round grade up to the next multiple of 5.
If the value of grade is less than 38, no rounding occurs as the result will still be a failing grade.
For example, grade=84 will be rounded to 85 but grade=29 will not be rounded because the rounding would result in a number that is less than 40.

Given the initial value of grade for each of Sam’s n students, write code to automate the rounding process. For each grade, round it according to the rules above and print the result on a new line.

Input Format
The first line contains a single integer denoting n (the number of students).
Each line i of the n subsequent lines contains a single integer, grade, denoting student i’s grade.

Output Format
For each grade of the n grades, print the rounded grade on a new line.

vector < int > Solve(vector < int > grades)
{

for (int i = 0; i < grades.size(); i++)
{
if( grades[i] >= 38 && grades[i] % 5 >= 3 )
{
}
else
{
}
}

}

int main()
{
int studentCount;
cin >> studentCount;

{